地址DB28.DBX12.2一直置位1,它是在FB205的IO点输出的,如图1
而FB块里关于这个点的程序如下,请问这句表示什么意思?谢谢
如何使这个位复位?
L P##IO_LubricationEnd
LAR1
TAR2
+AR1
L B [AR1,P#1.0]
T #ds_ANYPointer.DTP
L W [AR1,P#2.0]
T #ds_ANYPointer.LEN
L W [AR1,P#4.0]
T #ds_ANYPointer.DBN
L D [AR1,P#6.0]
T #ds_ANYPointer.PTR
//
L P##P_LubricationEnd
LAR1
L B#16#10
T B [AR1,P#0.0]
L #ds_ANYPointer.DTP
T B [AR1,P#1.0]
L #ds_ANYPointer.LEN
T W [AR1,P#2.0]
L #ds_ANYPointer.DBN
T W [AR1,P#4.0]
L #ds_ANYPointer.PTR
T D [AR1,P#6.0]
L P##IO_Valve
LAR1
TAR2
+AR1
L B [AR1,P#1.0]
T #ds_ANYPointer.DTP
L W [AR1,P#2.0]
T #ds_ANYPointer.LEN
L W [AR1,P#4.0]
T #ds_ANYPointer.DBN
L D [AR1,P#6.0]
T #ds_ANYPointer.PTR
//
L P##P_Valve
LAR1
L B#16#10
T B [AR1,P#0.0]
L #ds_ANYPointer.DTP
T B [AR1,P#1.0]
L #ds_ANYPointer.LEN
T W [AR1,P#2.0]
L #ds_ANYPointer.DBN
T W [AR1,P#4.0]
L #ds_ANYPointer.PTR
T D [AR1,P#6.0]
楼主最近还看过